Inequality Quiz 1 for Banking and Insurance Exams
If you are preparing for Government Recruitment or Entrance exams, you will likely need to solve a section on Reasoning. Inequality Quiz 1 for Banking and Insurance Exams will help you learn concepts on important topics in Logical Reasoning - Inequality. This Inequality Quiz 1 is important for exams such as IBPS PO, IBPS SO, IPPB, RBI Assistant, LIC, SBI PO, SBI Clerk, Syndicate Executive Exam etc.
Direction (1-10): In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.
A. Only conclusion I follows
B. Only conclusion II follows
C. Either conclusion I or II follows
D. Neither conclusion I nor II follows
E. Both conclusion I and II follows
Direction (1-10): In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.
A. Only conclusion I follows
B. Only conclusion II follows
C. Either conclusion I or II follows
D. Neither conclusion I nor II follows
E. Both conclusion I and II follows
- Statement:
M > K > T= P < S = R
Conclusions:
I. M > P
II. R > T - Statement:
R< L = T > S , V < G < R
Conclusions:
I. S > G
II. G < T - Statements:
D = K > R > T, Q < P = T
Conclusions:
I. D > P
II. R > Q - Statements:
M < N < R= J < K = L
Conclusions:
I. J > M
II. M = J - Statements:
A > N < R = Q, N < S = K
Conclusions:
I. A > K
II. S < Q - Statement: P ≤ Q = R > S > T
Conclusions:
I. P < T
II. T < Q - Statement: L ≤ M < N > O = P
Conclusion:
I. P < N
II. O < M - Statement: J > K ≤ L = M < N
Conclusions:
I. K < N
II. K < M - Statement: P ≤Q = R, T > R = S
Conclusions:
I. P = S
II. P < S - Statement: P ≤ Q = R, T > R = S
Conclusions:
I. Q < T
II. P < S
- Ans. A.
M > K > T= P hence M>P follows.
T= P < S = R hence T < R so T < R does not follow - Ans. B.
We can't establish any specific relation between S & G.
So conclusion I does not follow.
G < R < L = T hence G < T follows. - Ans. E.
D = K > R > T=P hence D > P follows.
Q < P = T < R hence R > Q follows. - Ans. C.
M < N < R= J so M < J hence either M<J or M=J follows. - Ans. D.
We can't establish any specific relation between A & K. So conclusion I does not follow.
We can't establish any specific relation between S & Q. So conclusion II does not follow. - Ans. B
P ≤ Q = R > S > T
For conclusion I: I. P < T (false) no relation between P & T
For conclusion II: Q = R > S > T II. T < Q (true) T is smaller than Q Hence,
only conclusion II follows - Ans. A
L ≤ M < N > O = P For conclusion I - N > O = P
I. P < N (true) For conclusion II - M < N > O
II. O < M (false) Hence, only conclusion I follows - Ans. A
J > K ≤ L = M < N
For conclusion: I. K < N (true) K ≤ L = M
For conclusion II. K < M (false)
Here, K is either smaller or equal to M.
So, this is not true.
Hence, the only conclusion I follows. - Ans. C
P ≤Q = R, T > R = S
by combining both the statement we get,
P ≤ Q = R = S < T
For both the conclusion,
P ≤Q = S < T P ≤ S
I. P = S
II. P < S So, both the conclusion make complementary pairs,
hence either I or II conclusion follows. - Ans. A
P ≤ Q = R, T > R = S
by combining both the statement we get,
P≤ Q = R = S, R < T
For Conclusion I,
Q < T I. Q < T (true)
For conclusion II,
we get P ≤ S II. P < S (false)
Hence, only conclusion I follows
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